Question
Ten years ago, A was half of B in age. If the ratio of their present ages is 3:4, what will be the total of their present ages?
Answer: Option B
- Let the ages of A and B 10 years ago be X and 2X years respectively.
Then, X +10 = 3 4 (X - 10) = 3(2X - 10) 2X = 10 X = 5 2X + 10 4
Sum of their present ages = (X + 10) + (2X + 10) = (3X + 20) = 35 years.
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- Let the ages of A and B 10 years ago be X and 2X years respectively.
Then, X +10 = 3 4 (X - 10) = 3(2X - 10) 2X = 10 X = 5 2X + 10 4
Sum of their present ages = (X + 10) + (2X + 10) = (3X + 20) = 35 years.
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