Question
A man is 24 years older than his son. In two years, his age will be twice the age of his son. The present age of the son is:
Answer: Option A
- Let the son’s present age be X years. Then, man’s present age = (X +24) years
(X + 24) + 2 = 2 (X + 2) X + 26 = 2X + 4
X = 22
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- Let the son’s present age be X years. Then, man’s present age = (X +24) years
(X + 24) + 2 = 2 (X + 2) X + 26 = 2X + 4
X = 22
Was this answer helpful ?
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