Question
Solve:4yz(z2+6z−16)÷2y(z+8)
Answer: Option C
:
C
Given, the expression is
4yz(z2+6z−16)2y(z+8).
First, we will factorise (z2+6z−16).
Comparing the above expression with the identity x2+(a+b)x+ab, we note that,(a+b)=6andab=−16.
Since,
8+(−2)=6and(8)(−2)=−16,
the expression, z2+6z−16
=z2+8z−2z−16
=z(z+8)−2(z+8)
=(z−2)(z+8) . . . (i)
By substituting (i) in the given expression, we get
=4yz(z−2)(z+8)2y(z+8)
=4×y×z×(z−2)×(z+8)2×y×(z+8)
=2z(z−2)
Was this answer helpful ?
:
C
Given, the expression is
4yz(z2+6z−16)2y(z+8).
First, we will factorise (z2+6z−16).
Comparing the above expression with the identity x2+(a+b)x+ab, we note that,(a+b)=6andab=−16.
Since,
8+(−2)=6and(8)(−2)=−16,
the expression, z2+6z−16
=z2+8z−2z−16
=z(z+8)−2(z+8)
=(z−2)(z+8) . . . (i)
By substituting (i) in the given expression, we get
=4yz(z−2)(z+8)2y(z+8)
=4×y×z×(z−2)×(z+8)2×y×(z+8)
=2z(z−2)
Was this answer helpful ?
More Questions on This Topic :
Question 1. Divide m2+7m−60 by (m−5).....
Question 2. On dividing (24xy2)(z2) by 6yz2, we get....
Question 3. Find the common factor between
2t,3t2and 4.....
Question 7. Substituting x=−3 in (x2)−5x gives
___....
Question 8. One of the factors of x2−2x−15 is:....
Question 10. 5x+10y is the expanded form of 5(x+2y).....
Latest Videos
Latest Test Papers
Submit Solution