Find the value of the given expression ( x 3 + 2 x 2 + 3 x ) ÷ 2 x Options: A . &nbsp(x2+2x+3)2 B . &nbsp12 C . &nbsp(x2+2x+3) D . &nbsp1

Answer: Option A : A Divide all the terms of the expression ( x 3 + 2 x 2 + 3 x ) separately by 2 x . x 3 2 x = x 2 2 ; 2 x 2 2 x = x ; 3 x 2 x = 3 2 . Therefore, ( x 3 + 2 x 2 + 3 x ) 2 x = x 2 2 + x + 3 2 = ( x 2 + 2 x + 3 ) 2

Find the value of the given expression (x3+2x2+3x)÷2x

Question

Find the value of the given expression

(x^{3} + 2 x^{2} + 3 x) \div 2 x

Options:

A . (x2+2x+3)2

B . 12

C . (x2+2x+3)

D . 1

Answer: Option A
:
A
Divide all the terms of the expression

(x^{3} + 2 x^{2} + 3 x)

separately by

2 x

\frac{x^{3}}{2 x} = \frac{x^{2}}{2}

;

\frac{2 x^{2}}{2 x} = x

;

\frac{3 x}{2 x} = \frac{3}{2}

.
Therefore,

\frac{(x^{3} + 2 x^{2} + 3 x)}{2 x} = \frac{x^{2}}{2} + x + \frac{3}{2} = \frac{(x^{2} + 2 x + 3)}{2}

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