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Question
Solution of the equation xdy=(y+xf(yx)f(yx))dx
Options:
A .  f(xy)=cy
B .  f(yx)=cx
C .  f(yx)=cxy
D .  f(yx)=0
Answer: Option B
:
B
We have, xdy=(y+xf(yx)f(yx))dx
dydx=yx+f(yx)f(yx)which is homogenous
Putting y=vxdydx=v+xdvdx, we obtain
v+xdvdx=v+f(v)f(v)f(v)f(v)dv=dxx
Integrating, we get log f(v)=logx+logc
logf(v)=logcxf(yx)=cx

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