Question
sin A−2 sin3A2 cos3A−cos A=
Answer: Option C
:
C
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:
C
sin A−2 sin3A2 cos3A−cos A=sin A(1−2 sin2A)cos A(2 cos2A−1)
=sin A(sin2A+cos2A−2 sin2A)cos A(2 cos2A−(sin2A+cos2A))
=sin A(cos2A−sin2A)cosA(cos2A−sin2A)
=tan A
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