Question
Sarthak completed a marathon in 4 hours and 35 minutes. The marathon consisted of a 10 km run followed by 20 km cycle ride and the remaining distance again a run. He ran the first stage at 6 km/hr and then cycled at 16 km/ hr. How much distance did Sarthak cover in total, if his speed in the last run was just half that of his first run?
Answer: Option A
Answer: (a)Let the total distance be x km.Time = $\text"Distance"/ \text"Speed"$According to the question,$10/6 + 20/16 + {x - 30}/3$= 4$35/60 = 4{7}/12$$5/3 + 5/4 + x/3 - 10 = 55/12$$x/3 + 5/3 + 5/4 - 10 = 55/12$$x/3 + ({20 + 15 - 120}/12) = 55/12$$x/3 - 85/12 = 55/12$$x/3 = 85/12 + 55/12 = 140/12$$x = 140/12 × 3$ = 35 km.
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Answer: (a)Let the total distance be x km.Time = $\text"Distance"/ \text"Speed"$According to the question,$10/6 + 20/16 + {x - 30}/3$= 4$35/60 = 4{7}/12$$5/3 + 5/4 + x/3 - 10 = 55/12$$x/3 + 5/3 + 5/4 - 10 = 55/12$$x/3 + ({20 + 15 - 120}/12) = 55/12$$x/3 - 85/12 = 55/12$$x/3 = 85/12 + 55/12 = 140/12$$x = 140/12 × 3$ = 35 km.
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