Question
A is faster than B. A and B each walk 24 km. The sum of their speeds is 7 km/hr and the sum of times taken by them is 14 hours. Then A's speed is equal to:
Answer: Option A
Answer: (a)Let, A's speed = x kmph.B's speed = (7 - x) kmphTime = $\text"Distance"/ \text"Speed"$According to the question,$24/x + 24/{7 - x} = 14$$24({7 - x + x}/{x(7 - x)})$ = 14${24 × 7}/{x(7 - x)}$ = 14x (7 - x) = 12 = 4 × 3 or 3 × 4x (7 - x) = 4 (7 - 4) or 3 (7 - 3)x = 4 or 3A's speed = 4 kmph.
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Answer: (a)Let, A's speed = x kmph.B's speed = (7 - x) kmphTime = $\text"Distance"/ \text"Speed"$According to the question,$24/x + 24/{7 - x} = 14$$24({7 - x + x}/{x(7 - x)})$ = 14${24 × 7}/{x(7 - x)}$ = 14x (7 - x) = 12 = 4 × 3 or 3 × 4x (7 - x) = 4 (7 - 4) or 3 (7 - 3)x = 4 or 3A's speed = 4 kmph.
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