Reynolds analogy is given by Options: A . &nbspNu x/ (Re x) (Pr x) = 5 St X = – 2 C F x B . &nbspNu x/ 2 (Re x) (Pr x) = 4 St X = – C F x /3 C . &nbspNu x/ (Re x) (Pr x) = St X = – ½ C F x D . &nbspNu x/ (Re x) (Pr x) = 2 St X = – C F x /4

Reynolds analogy is given by

Question

Reynolds analogy is given by

Options:

A . Nu x/ (Re x) (Pr x) = 5 St X = – 2 C F x

B . Nu x/ 2 (Re x) (Pr x) = 4 St X = – C F x /3

C . Nu x/ (Re x) (Pr x) = St X = – ½ C F x

D . Nu x/ (Re x) (Pr x) = 2 St X = – C F x /4

Answer: Option C
Answer: (c).Nu x/ (Re x) (Pr x) = St X = – ½ C F x

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