Question
Pankaj travels 10 m in North direction, he turns right and travels 20 m. Again he turns towards right and travels 25 m. Then, he turns towards left and travels 15 m. In which direction and how far is Pankaj from his original position?
Answer: Option E
Answer: (e)
According to the question, the direction diagram will be as follows.
A = Starting point, E = Finishing point DE = 15 m,
BC = FD = 20 m FE = FD + DE = 20 + 15 = 35 m
AF = BF - AB = 25 - 10 = 15 m
Therefore, Required distance, AE = $√{(AF)^2 + (FE)^2}$
= $√((15)^2 + (35)^2)$
= $√{(225 + 1225)}$
= $√1450$
and the direction is South-East
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Answer: (e)
According to the question, the direction diagram will be as follows.
A = Starting point, E = Finishing point DE = 15 m,
BC = FD = 20 m FE = FD + DE = 20 + 15 = 35 m
AF = BF - AB = 25 - 10 = 15 m
Therefore, Required distance, AE = $√{(AF)^2 + (FE)^2}$
= $√((15)^2 + (35)^2)$
= $√{(225 + 1225)}$
= $√1450$
and the direction is South-East
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