Question
Rajnikanth left his home foe office in car. He drove 15 km straight towards North and then turned Eastwards and covered 8 km. He, then turned to left and covered 1 km. He again turned left and drove for 20 km and reached office. How far and in what direction in his office from the home?
Answer: Option C
Answer: (c)
According to the question, the direction diagram will be as follows.
Now, AB = 15 km, CD = BF = 1 km
AF = AB + BF = 15 + 1 = 16 km
DE = 20 km DF = BC = 8 km
EF = DE - DF = 20 - 8 = 12 km
Therefore, Required distance, AE = $√{(AF)^2 + (EF)^2}$
= $√{(16)^2 + (12)^2}$
= $√{(256 + 144)}$ = √400 = 20 km
So, his office is 20 km North - West.
Was this answer helpful ?
Answer: (c)
According to the question, the direction diagram will be as follows.
Now, AB = 15 km, CD = BF = 1 km
AF = AB + BF = 15 + 1 = 16 km
DE = 20 km DF = BC = 8 km
EF = DE - DF = 20 - 8 = 12 km
Therefore, Required distance, AE = $√{(AF)^2 + (EF)^2}$
= $√{(16)^2 + (12)^2}$
= $√{(256 + 144)}$ = √400 = 20 km
So, his office is 20 km North - West.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution