Question
Oshin has 36 chocolates. Among how many possible sets of children can she distribute the chocolate so that each child gets an equal number of chocolates without breaking the chocolates? [2 MARKS]
Answer:
:
Steps: 1 Mark
Answer: 1 Mark
Oshin can distribute the chocolates by finding the factors of 36: Each of the factors will divide the chocolates in an equal number of parts, So each child will get an equal number of chocolates.
We can find the factors of 36 in the following way:
36=1×36
36=2×18
36=3×12
36=4×9
36=6×6
Stop here, because both the factors (6) are same.
Thus, the factors are 1, 2, 3, 4, 6, 9, 12, 18 and 36. So she can distribute in 9 possible sets, depending on how many children form one set.
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:
Steps: 1 Mark
Answer: 1 Mark
Oshin can distribute the chocolates by finding the factors of 36: Each of the factors will divide the chocolates in an equal number of parts, So each child will get an equal number of chocolates.
We can find the factors of 36 in the following way:
36=1×36
36=2×18
36=3×12
36=4×9
36=6×6
Stop here, because both the factors (6) are same.
Thus, the factors are 1, 2, 3, 4, 6, 9, 12, 18 and 36. So she can distribute in 9 possible sets, depending on how many children form one set.
Was this answer helpful ?
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