Question
Find the least number which when divided by 32, 64 & 128 leaves the remainder of 8.
Answer: Option C
:
C
The smallest number that is divisible by32, 64, 128 is the LCM of32, 64, 128.
LCM of 32, 64, 128 =
= 2×2×2×2×2×2×2
=128
When 128 is divided by 32, 64 & 128 there is no remainder. So, to get remainder 8 when divided by32, 64 & 128, 8 is to be added to 128i.e., 128+8 = 136
Was this answer helpful ?
:
C
The smallest number that is divisible by32, 64, 128 is the LCM of32, 64, 128.
LCM of 32, 64, 128 =
= 2×2×2×2×2×2×2
=128
When 128 is divided by 32, 64 & 128 there is no remainder. So, to get remainder 8 when divided by32, 64 & 128, 8 is to be added to 128i.e., 128+8 = 136
Was this answer helpful ?
More Questions on This Topic :
Question 5. Define odd numbers. [1 MARK]....
Question 9. What do you mean by prime factorization?....
Latest Videos
Latest Test Papers
Submit Solution