Question
On a circle of radius 3 cm draw its two chords. Then construct the perpendicular bisector of these chords. Where do they meet? [4 MARKS]
Answer:
:
Construction of circle: 1 Mark
Construction of chords: 1 Mark
Construction of bisector: 1 Mark
Meeting point: 1 Mark
i)Mark any point C on the sheet. Now, by adjusting the compassup to 3 cm and by putting the pointer of compass,draw the circle. It is the required circle of 3 cm radius.
ii)Take any two chords AB and CD in the circle.
iii)Taking A and B as centres and with radius more than half of AB, draw arcs on both sides of AB, intersecting each other at E, F. Join EF which is the perpendicular bisector of AB.
iv)Taking C and D as centres and with radius more than half of CD, draw arcs on both sides of CD, intersecting each other at G andH . Join GH which is the perpendicular bisector of CD.
Now, we find thatEF and GH meet at the centre of circle O.
Was this answer helpful ?
:
Construction of circle: 1 Mark
Construction of chords: 1 Mark
Construction of bisector: 1 Mark
Meeting point: 1 Mark
i)Mark any point C on the sheet. Now, by adjusting the compassup to 3 cm and by putting the pointer of compass,draw the circle. It is the required circle of 3 cm radius.
ii)Take any two chords AB and CD in the circle.
iii)Taking A and B as centres and with radius more than half of AB, draw arcs on both sides of AB, intersecting each other at E, F. Join EF which is the perpendicular bisector of AB.
iv)Taking C and D as centres and with radius more than half of CD, draw arcs on both sides of CD, intersecting each other at G andH . Join GH which is the perpendicular bisector of CD.
Now, we find thatEF and GH meet at the centre of circle O.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution