Milk turns sour at 40 ∘ C three times as faster as 0 ∘ C. Hence, E a in the process of turning of milk sour is Options: A . &nbsp2.303×2×313×27340log3 B . &nbsp2.303×2×313×27340log(1/3) cal C . &nbsp2.303×2×40273×313log3 cal D . &nbspNone of these

Answer: Option A : A K 40 ∘ C = A e − E a / R × 313 K 0 ∘ C = A e − E a / R × 273 3 = e − E a / R × ( 1 / 313 − 1 / 273 ) On taking logs on both sides, you get the required answer

Milk turns sour at 40∘C three times as faster as 0∘C. Hence, Ea in

Question

Milk turns sour at

40^{\circ}

C three times as faster as

0^{\circ}

C. Hence,

E_{a}

in the process of turning of milk sour is

Options:

A . 2.303×2×313×27340log3

B . 2.303×2×313×27340log(1/3) cal

C . 2.303×2×40273×313log3 cal

D . None of these

Answer: Option A
:
A

K_{40^{\circ} C} = A e^{- E a / R \times 313} K_{0^{\circ} C} = A e^{- E a / R \times 273} 3 = e^{- E a / R \times (1 / 313 - 1 / 273)}

On taking logs on both sides, you get the required answer

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