Question
Velocity constant of a reaction at 290 K was found to 3.2×10−3sec−1. When the temperature is raised to 310 K, it will be about:
Answer: Option D
:
D
From the Arhenius eqn, we know that the rate of a reaction doubles for every 10 K rise in temperature.
k2k1=22⇒k2=3.2×10−3×4=1.28×10−2sec−1
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:
D
From the Arhenius eqn, we know that the rate of a reaction doubles for every 10 K rise in temperature.
k2k1=22⇒k2=3.2×10−3×4=1.28×10−2sec−1
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