Question
limx→π2cotx−cosx(π−2x)3 is equal to
Answer: Option C
:
C
limx→π2cotx−cosx(π−2x)3
Let x=π2+t
If x→π2,t→0
limt→0sint−tant−8t3
=limt→0(t−t33!+t55!+…)−(t+t33+2t515+…)−8t3
=116
We can put x=π2−t and we'll get L.H.L also same.
Since L.H.L = R.H.L the limit exists and is =116
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:
C
limx→π2cotx−cosx(π−2x)3
Let x=π2+t
If x→π2,t→0
limt→0sint−tant−8t3
=limt→0(t−t33!+t55!+…)−(t+t33+2t515+…)−8t3
=116
We can put x=π2−t and we'll get L.H.L also same.
Since L.H.L = R.H.L the limit exists and is =116
Was this answer helpful ?
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