Question
Let f(x)=loge{u(x)v(x)},u′(2)=4,v′(2)=2,u(2)=2,v(2)=1,then f′(2) is equal to
Answer: Option A
:
A
f(x)=loge{u(x)v(x)}
=logeu(x)−logev(x)
∴f′(x)=u′(x)u(x)−v′(x)v(x)
f′(2)=u′(2)u(2)−v′(2)v(2)
=42−21
=2−2=0
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:
A
f(x)=loge{u(x)v(x)}
=logeu(x)−logev(x)
∴f′(x)=u′(x)u(x)−v′(x)v(x)
f′(2)=u′(2)u(2)−v′(2)v(2)
=42−21
=2−2=0
Was this answer helpful ?
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