Question
Let f be a function satisfying 2f(x)−3f(1x)=x2 for any x≠0, then the value of f(2) is
Answer: Option B
:
B
2f(x)−3f(1x)=x2……(i)Replacing x by 1x2f(1x)−3f(x)=1x2……(ii)
Solving (i) and (ii) we get
−5f(x)=2x2+3x2f(x)=−15(2x2+3x2)∴f(2)=−15(8+34)=−74
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:
B
2f(x)−3f(1x)=x2……(i)Replacing x by 1x2f(1x)−3f(x)=1x2……(ii)
Solving (i) and (ii) we get
−5f(x)=2x2+3x2f(x)=−15(2x2+3x2)∴f(2)=−15(8+34)=−74
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