In the given parallelogram ABCD, ΔABD≅ΔBCD.

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Question

$In the given parallelogram A B C D, Δ A B D ≅ Δ B C D .$

Options:

A . True

B . False

C .

Δ A B C ≅ Δ A D C

D .

Area of Δ A B D = \frac{1}{2} \times Area of Δ A B C

Answer: Option B
:
B

Consider Δ A B D and Δ C D B, A B = C D (Opposite sides of parallelogram) A D = C B (Opposite sides of parallelogram) ∠ A B D = ∠ C D B (Alternate angles) . ∴ Δ A B D ≅ Δ C D B

Hence, the given statement is false as the vertices are not given in corresponding sequence in question.

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