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In the given image, segment AB has been divided in the ratio 3:2. This is done by
1. Draw any ray AX making acute angle with AB.
2. Draw a ray BY parallel to AX by making ABY=BAX
3. Locate the points A1,A2,A3...A3 on AX and  B1,B2 on BY such that AA1=A1A2=BB1=B1B2
4. Join A3B2by using which of the properties of parallel lines?
In The Given Image, Segment AB Has Been Divided In The Ratio...


Options:
A .   Corresponding angle are equal
B .   Alternate interior angles are equal
C .   Co-interior angle are supplementary
D .   Perpendicular bisector theorem
Answer: Option B
:
B
In The Given Image, Segment AB Has Been Divided In The Ratio...
Here we use alternate interior angles are equal then the lin4es are parallel and XAB=ABY as AX parallel to BY.

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