A triangle ABC with sides BC =7cm, ∠B=45∘,∠A=105∘ is given. The image of constructing a similar triangle of ΔABC whose sides are 34 times the corresponding sides of the ΔABC is given below. The condition used to draw A'C' parallel to AC:
Options:
A .  
Corresponding angles are equal
B .  
Alternate interior angles are equal
C .  
Co-interior angles are supplementary
D .  
Perpendicular bisector theorem
Answer: Option A : A Here we use the principle that when corresponding angles are equal, the lines are parallel. ∠A′C′B=∠ACB→ AC||A'C'.
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