A triangle A B C with B C = 6 c m , A B = 5 c m and ∠ A B C = 60 ∘ . The image of constructing a similar triangle of Δ A B C whose sides are 3 4 times the corresponding sides of the Δ A B C is given below. Arrange the steps of construction in the correct order. 1. Join B 4 C and raw a line through B 3 (the third point, 3 being smaller of 4 in 3 4 ) parallel to B 4 C to intersect BC at C'. 2. Draw any ray B X making an acute angle with BC on the side opposite to the vertex A. 3. Locate 4 (the greater of 3 and 4 in 3 4 ) points B 1 , B 2 , B 3 and B 4 on BX so that B B 1 = B 1 B 2 = B 2 B 3 = B 3 B 4 4. Draw a line through C' parallel to the line CA to intersect BA at A'. Options: A . &nbsp 1, 2, 3, 4 B . &nbsp 2, 1, 3, 4 C . &nbsp 2, 3, 1, 4 D . &nbsp 2, 4, 1, 3

Answer: Option C : C Steps to be followed to for the construction of a similar triangle of Δ A B C is given below. 1. Draw any ray BX making an acute angle with BC on the side opposite to the vertex A. 2.Locate 4(the greater of 3 and 4 in 3 4 ) points B 1 , B 2 , B 3 and B 4 on BX so that B B 1 = B 1 B 2 = B 2 B 3 = B 3 B 4 3.Join B 4 C and raw a line through B 3 ( the third point, 3 being smaller of 4 in 3 4 ) parallel to B 4 C to intersect BC at C'. 4.Draw a line through C' parallel to the line CA to intersect BA at A'.

A triangle ABC with BC=6 cm,AB=5 cm and ∠ABC=60∘. The image of constructin

Question

A triangle $A B C$ with $B C = 6 c m, A B = 5 c m$ and $∠ A B C = 60^{\circ}$ . The image of constructing a similar triangle of $Δ A B C$ whose sides are $\frac{3}{4}$ times the corresponding sides of the $Δ A B C$ is given below.

Arrange the steps of construction in the correct order.
1. Join $B_{4} C$ and raw a line through $B_{3}$
(the third point, 3 being smaller of 4 in $\frac{3}{4}$ ) parallel to $B_{4} C$ to intersect BC at C'.
2. Draw any ray $B X$ making an acute angle with BC on the side opposite to the vertex A.
3. Locate 4 (the greater of 3 and 4 in $\frac{3}{4}$ ) points $B_{1}, B_{2}, B_{3} and B_{4}$ on BX so that $B B_{1} = B_{1} B_{2} = B_{2} B_{3} = B_{3} B_{4}$
4. Draw a line through C' parallel to the line CA to intersect BA at A'.