Question
Answer:
:
In quadrilateral ABCD,
∴∠ABC+∠BCD+∠CDA+∠DAB=360∘40∘+50∘+∠CDA+70∘=360∘⇒∠CDA+160∘=360∘⇒∠CDA=360∘−160∘=200∘
Now,∠CDA+∠ADC=360∘(∵ Angle at a point)
200∘+x=360∘⇒x=360∘−200∘⇒x=160∘
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:
In quadrilateral ABCD,
∴∠ABC+∠BCD+∠CDA+∠DAB=360∘40∘+50∘+∠CDA+70∘=360∘⇒∠CDA+160∘=360∘⇒∠CDA=360∘−160∘=200∘
Now,∠CDA+∠ADC=360∘(∵ Angle at a point)
200∘+x=360∘⇒x=360∘−200∘⇒x=160∘
Was this answer helpful ?
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