Question
In the figure S1 and S2 are two narrow slits illuminated by light of wavelength ′λ′ and they ae in phase. `P' is a point on the screen which corresponds to 4th minimum then the path difference S2P–S1P is equal to
Answer: Option C
:
C
x=(2n−1)λ2;n=4
=(2×4−1)λ2
=(8−1)λ2
=7λ2
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:
C
x=(2n−1)λ2;n=4
=(2×4−1)λ2
=(8−1)λ2
=7λ2
Was this answer helpful ?
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