Question
A thin equiconvex lens is made of glass of R.I 1.5 and its focal length is 0.2 If it acts a concave lens of 0.5 m focal length when dipped in a liquid, the R.I of liquid is
Answer: Option B
:
B
−f1fa=(μ5−1)(μsμl−1)−2.5=0.5(1.5μl−1)−0.50.2=1.5−1(1.5μ1−1)1.5μl−1=−151.5μl=1−15=45μl=74=7540=158
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:
B
−f1fa=(μ5−1)(μsμl−1)−2.5=0.5(1.5μl−1)−0.50.2=1.5−1(1.5μ1−1)1.5μl−1=−151.5μl=1−15=45μl=74=7540=158
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