In the above problem, if the speed of m2 is 50 cm/s the distance covered by

Question

In the above problem, if the speed of

m_{2}

is 50 cm/s the distance covered by

m_{1}

in 0.4 s will be

Options:

A . 40 cm

B . 20 cm

C . 10 cm

D . 80 cm

Answer: Option A
:
A
Distance covered by

m_{2} = 50 c m / s \times 0.4 s = 20 c m

Since the

m_{1}

mass cover double distance therefore

S = 2 \times 20 = 40 c m

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