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A cricket ball of mass 150 gm is moving with a velocity of 12 m/s and is hit by a bat so that the ball is turned back with a velocity of 20 m/s. The force of blow acts for 0.01s on the ball. The average force exerted by the bat on the ball is
Options:
A .  480 N
B .  600 N
C .  500 N
D .  400 N
Answer: Option A
:
A
v1=12 m\s and v2=+20m/s [because direction is reversed]
m=150gm=0.15kg,t=0.01sec
Force exerted by the bat on the ball F=m[v2v1]t=0.15[20(12)0.01]=480Newton

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