Question
Answer:
:
Given, ∠RQY=60∘
∠SRQ=∠RQY [SR∥PY, RQ is the transversal]
⇒∠R=60∘
∴∠S=180∘−∠R=180∘−60∘=120∘ [∵ adjacent angles are supplementary]
Also, SR = 15 cm
⇒ PQ = 15 cm [∵ opposite sides of a parallelogram are equal]
And PS = 11 cm
⇒ QR = 11 cm [∵ opposite sides of a parallelogram are equal]
PR is bisected by SQ, so PR=2×PO=2×6=12cm
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Given, ∠RQY=60∘
∠SRQ=∠RQY [SR∥PY, RQ is the transversal]
⇒∠R=60∘
∴∠S=180∘−∠R=180∘−60∘=120∘ [∵ adjacent angles are supplementary]
Also, SR = 15 cm
⇒ PQ = 15 cm [∵ opposite sides of a parallelogram are equal]
And PS = 11 cm
⇒ QR = 11 cm [∵ opposite sides of a parallelogram are equal]
PR is bisected by SQ, so PR=2×PO=2×6=12cm
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