The diagonals of a rhombus are 8 cm and 15 cm. Find its side.

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The diagonals of a rhombus are 8 cm and 15 cm. Find its side.

Answer:
:
Given, AC = 15 cm, BD = 8 cm.

The Diagonals Of A Rhombus Are 8 Cm And 15 Cm. Find Its Side...

Since, the diagonals of a rhombus bisect each other at

90^{\circ}

, therefore in the

Δ A O B

, we have

A B^{2} = O A^{2} + O B^{2} \Rightarrow A B^{2} = {(\frac{15}{2})}^{2} + {(\frac{8}{2})}^{2} = (7.5)^{2} + (4)^{2} = 56.25 + 16 \Rightarrow A B^{2} = 72.25 \Rightarrow A B = \sqrt{72.25} \Rightarrow A B = 8.5 c m

Since it is a rhombus, the length of each side is 8.5 cm.

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