Question
In how many different ways can four books A, B, C and D be arranged one above another in a vertical order such that the books A and B are never in continuous position?
Answer: Option B
THE NUMBER OF ARRANGEMENT IN WHICH A AND B ARE NOT TOGETHER
= TOTAL NUMBER OF ARRANGEMENTS
= NUMBER OF ARRANGEMENTS IN WHICH A AND B ARE TOGETHER =4!-3!X2! = 24-12 =12.
Was this answer helpful ?
THE NUMBER OF ARRANGEMENT IN WHICH A AND B ARE NOT TOGETHER
= TOTAL NUMBER OF ARRANGEMENTS
= NUMBER OF ARRANGEMENTS IN WHICH A AND B ARE TOGETHER =4!-3!X2! = 24-12 =12.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution