Question
A mixed doubles tennis game is to be played two teams(each consists of one male and one female) There are four married couples. No team is to consist a husband and his wife. What is the maximum number of games that can be played?
Answer: Option D
MARRIED COUPLES = MF MF MF MF
AB CD EF GH
POSSIBLE TEAMS = AD CB EB GB
AF CF ED GD
AH CH EH GF S
SINCE ONE MALE CAN BE PAIRED WITH 3 OTHER FEMALE, TOTAL TEAMS = 4×3 = 12.
TEAM AD CAN PLAY ONLY WITH CB,CF,CH,EB,EH,GB,GF(7 TEAMS )
TEAM AD CANNOT PLAY WITH AF, AH, ED AND GD
THE SAME WILL APPLY WITH ALL TEAMS, SO NUMBER OF TOTAL MATCHES = 12×7 = 84.
BUT EVERY MATCH INCLUDES 2 TEAMS, SO THE ACTUAL NUMBER OF MATCHES = 84/2 = 42.
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MARRIED COUPLES = MF MF MF MF
AB CD EF GH
POSSIBLE TEAMS = AD CB EB GB
AF CF ED GD
AH CH EH GF S
SINCE ONE MALE CAN BE PAIRED WITH 3 OTHER FEMALE, TOTAL TEAMS = 4×3 = 12.
TEAM AD CAN PLAY ONLY WITH CB,CF,CH,EB,EH,GB,GF(7 TEAMS )
TEAM AD CANNOT PLAY WITH AF, AH, ED AND GD
THE SAME WILL APPLY WITH ALL TEAMS, SO NUMBER OF TOTAL MATCHES = 12×7 = 84.
BUT EVERY MATCH INCLUDES 2 TEAMS, SO THE ACTUAL NUMBER OF MATCHES = 84/2 = 42.
Was this answer helpful ?
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