Question
In a class of 60 where boys are twice that of girls, Raman ranked 17th from the top. If there are 9 boys ahead of Raman, how many girls are after her in the rank ?
Answer: Option B
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In a class of 60 students, where boys are twice that of girls, the total number of girls is given by:
Total number of girls = 60/3 = 20
Since Raman is ranked 17th from the top, there are 9 boys ahead of him.
Therefore, the number of girls ahead of Raman = 20 – 9 = 11
Hence, the number of girls after Raman = 20 – 11 = 9
Therefore, the number of girls after Raman in the rank = 9.
Hence, option B - 12 is the correct answer.
Explanation:
• Number of students in the class = 60
• Number of boys = 2x
• Number of girls = x
• Raman’s rank = 17th from the top
• Number of boys ahead of Raman = 9
• Number of girls ahead of Raman = 20 – 9 = 11
• Number of girls after Raman = 9
• Therefore, the correct answer is Option B - 12.
If you think the solution is wrong then please provide your own solution below in the comments section .
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So x +2x=60,so x=20.ie; girls=20 and boys=40.Raman is in 17th rank.So total students in front of her is 16.Of which 9 are boys.So girls in front of her=16-9=7.Now, RAMAN is a GIRL.Including her 7+1=8 girls.So remaining girls,
20-8=12 are after her.
Boys are twice of girls =2x
Girls in class =x
So, to find girls
We conclude , x+2x=60,
3x =60, x =20.
Girls in class =20 , boys =2x =2×20=40
Upto 17 th rank, 9 boys is already ahead of him. So, Girls will ahead frm him = 17-9=8
Behind him girls will be =20-8=12
So there are 20 girls and 40 boys.
Raman is in 17th place and 9 boys are ahead him so there are 7 girls ahead him.
So the girls after him=20-7-1=>12