Question
If x=ey+ey+ey+ey+⋯∞
Answer: Option B
:
B
x=ey+x⇒loge x=y+x
∴1x=dydx+1
⇒dydx=1−xx
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:
B
x=ey+x⇒loge x=y+x
∴1x=dydx+1
⇒dydx=1−xx
Was this answer helpful ?
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