Question
If x=ya, y=zb, z=xc then find abc. If a = 12, b = 1288, then find the value of c. [4 MARKS]
Answer:
:
Steps: 1 Marks
Application: 1 Mark
Value of abc: 1 Mark
Value of c: 1 Mark
It is given that
x=ya,y=zb,z=xc
x=ya
=(zb)a (∵y=zb)
=zab
=(xc)ab (∵xc=z)
x=xabc ∵((am)n=amn)
⇒x1=xabc
As bases are equal, exponents are equal.
⇒abc=1
Now, it is also given that,
a = 12, b = 1288
a×b×c = 1
c = 1a×b
On substituting the values we get:
c = 112×1288
c = 28812
c = 24
Hence, the value of c is 24.
Was this answer helpful ?
:
Steps: 1 Marks
Application: 1 Mark
Value of abc: 1 Mark
Value of c: 1 Mark
It is given that
x=ya,y=zb,z=xc
x=ya
=(zb)a (∵y=zb)
=zab
=(xc)ab (∵xc=z)
x=xabc ∵((am)n=amn)
⇒x1=xabc
As bases are equal, exponents are equal.
⇒abc=1
Now, it is also given that,
a = 12, b = 1288
a×b×c = 1
c = 1a×b
On substituting the values we get:
c = 112×1288
c = 28812
c = 24
Hence, the value of c is 24.
Was this answer helpful ?
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