Question
In a race Karan covers 1m in 1st second, in the next second he covers twice the distance he covered in 1st second, in 3rd second he covers twice the distance which he covered in 2nd second and he continues to run like this till six seconds. After that he slows down, as in 7th second he covers only half the distance which he covered in 6th second and in 8thsecond he covers half the distance which he covered in 7thsecond and he continuous in that manner. If Karan completes the race in 9 seconds, find the length of given track. [4 MARKS]
Answer:
:
Application: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Here are the distances covered by Karan in each second
1stsecond = 1m
2ndsecond =1×2=2m
Hence, the length of the track is 2 m.
3rdsecond =2×2= 4m
4thsecond =4×2= 8m
5thsecond = 8×2=16m
6thsecond = 16×2=32m
7thsecond =32÷2= 16m
8thsecond =16÷2= 8m
9thsecond =8÷2= 4m
Length of the given track = (1+2+4+8+16+32+16+8+4) m
⇒Length of the given track = 91 m
Hence, the length of the track is 91 m.
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:
Application: 1 Mark
Steps: 2 Marks
Answer: 1 Mark
Here are the distances covered by Karan in each second
1stsecond = 1m
2ndsecond =1×2=2m
Hence, the length of the track is 2 m.
3rdsecond =2×2= 4m
4thsecond =4×2= 8m
5thsecond = 8×2=16m
6thsecond = 16×2=32m
7thsecond =32÷2= 16m
8thsecond =16÷2= 8m
9thsecond =8÷2= 4m
Length of the given track = (1+2+4+8+16+32+16+8+4) m
⇒Length of the given track = 91 m
Hence, the length of the track is 91 m.
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