If x + y = 4, x2 + y2 = 14 and x > y. Then the correct value of x and y is? Options: A . &nbsp$$2 - \sqrt 2 ,\sqrt 3 $$ B . &nbsp$$3,1$$ C . &nbsp$$2 + \sqrt 3 ,2 - \sqrt 3 $$ D . &nbsp$$2 + \sqrt 3 ,2\sqrt 2 $$

If x + y = 4, x2 + y2 = 14 and x > y. Then the correct value of x and y is?

Question

If x + y = 4, x2 + y2 = 14 and x > y. Then the correct value of x and y is?

Options:

A . $$2 - \sqrt 2 ,\sqrt 3 $$

B . $$3,1$$

C . $$2 + \sqrt 3 ,2 - \sqrt 3 $$

D . $$2 + \sqrt 3 ,2\sqrt 2 $$

Answer: Option C

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