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If $${\left( {a + \frac{1}{a}} \right)^2} = 3{\text{,}}$$    then find the value of $${a^{30}}$$ + $${a^{24}}$$ + $${a^{18}}$$ + $${a^{12}}$$ + $${a^6}$$ + $$1$$ = ?
Options:
A .  0
B .  -27
C .  1
D .  -1
Answer: Option A

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