Question
If x=sin(2tan−12),y=sin(12tan−143) then
Answer: Option D
:
D
Let tan−12=α⇒x=sin2α=45y=sin(β2)=√1−cosβ2=√1−352=1√5
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:
D
Let tan−12=α⇒x=sin2α=45y=sin(β2)=√1−cosβ2=√1−352=1√5
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