If the height of a triangle is 10 cm and its area is 40 cm2, th

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If the height of a triangle is $10 c m$ and its area is $40 {c m}^{2}$ , then the base of the triangle is $6 c m$ .

Options:

A . True

B . False

C .

\sqrt{1463} {cm}^{2}

D .

24 \sqrt{3} {cm}^{2}

Answer: Option B
:
B

$Area of a triangle = \frac{1}{2} \times b a s e \times h e i g h t = 40$
$\Rightarrow b a s e = \frac{40 \times 2}{h e i g h t}$

$\Rightarrow b a s e = \frac{80}{10} = 8 c m$

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