Question
A triangular advertisement board has sides 11m, 15m and 6m. If the advertisement yields an earning of Rs1000/m2per month. In 3 and half years, the company will earn A√2. Find the value of A ___.
Answer: Option A
:
Using the Heron's formula, Area (A)= √s(s−a)(s−b)(s−c).
Semi-Perimeter (s) = a+b+c2 =11+15+62
=16 m
∴A=√16(16−11)(16−15)(16−6) =20√2 m2
3 and a half years = 12 x 3 + 6 = 42 months.
∴ Earning in 3 and a half years =20√2×1000×42 =Rs.840000√2
The value of A is 840000.
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:
Using the Heron's formula, Area (A)= √s(s−a)(s−b)(s−c).
Semi-Perimeter (s) = a+b+c2 =11+15+62
=16 m
∴A=√16(16−11)(16−15)(16−6) =20√2 m2
3 and a half years = 12 x 3 + 6 = 42 months.
∴ Earning in 3 and a half years =20√2×1000×42 =Rs.840000√2
The value of A is 840000.
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