Question
If the focal length of the objective lens and the eye lens are 4 mm and 25 mm respectively in a compound microscope. The length of the tube is 16 cm. Find its magnifying power for relaxed eye position
Answer: Option B
:
B
The image distance for the objective, in this case, is L−f0−fe as the focal lengths are not negligible compared to the length of the telescope.
By using m∞=(L−f0−fe)Df0fe
=(16−0.4−2.5)×250.4×2.5=327.5
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B
The image distance for the objective, in this case, is L−f0−fe as the focal lengths are not negligible compared to the length of the telescope.
By using m∞=(L−f0−fe)Df0fe
=(16−0.4−2.5)×250.4×2.5=327.5
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