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Question


If the eccentricity of a hyperbola is 2 and if the distance between the foci is 16, then its equation is 


Options:
A .   x2y2=4
B .   x2y2=8
C .   x2y2=16
D .   x2y2=32
Answer: Option D
:
D

Given that distance between foci, 2c =16
c=8; e=2 
a=ce=82=42b=c2a2=32=42


The equation of the hyperbola is
x232y232=1x2y2=32



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