If ST is parallel to QR, and PS = SQ = 3 cm, PT = 4 cm and QR = 10 cm,

Question

If ST is parallel to QR, and PS = SQ = 3 cm, PT = 4 cm and QR = 10 cm, what is the area of trapezoid STQR?

Options:

A . 12

B . 20

C . 30

D . 18

Answer: Option D
:
D
Option (d).
Triangle PST & PQR are similar.Thus,

\frac{P S}{P Q}

\frac{P T}{P R}

\Rightarrow

PR=8
Thus, PQR is a right angled triangle with sides-6,8,10
Area of trapezoid STQR= Area of triangle PQR- Area of triangle PST=

\frac{1}{2}

*6*8 -

\frac{1}{2}

*3*4. Answer is 18 cm

^{2}

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