If sinθ = $$\frac{a}{b}$$ then the value of secθ

Question

If sinθ = $$\frac{a}{b}$$ then the value of secθ - cosθ is? (where 0° < θ < 90°)

Options:

A . $$\frac{a}{{b\sqrt {{b^2} - {a^2}} }}$$

B . $$\frac{{{b^2}}}{{a\sqrt {{b^2} - {a^2}} }}$$

C . $$\frac{{{a^2}}}{{b\sqrt {{b^2} - {a^2}} }}$$

D . $$\frac{{\sqrt {{b^2} + {a^2}} }}{{\sqrt {{b^2} - {a^2}} }}$$

Answer: Option C

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