If $$sec\theta = x + \frac{1}{{4x}}$$ $$\left( {{0^ \circ } Options: A . &nbsp$$\frac{x}{2}$$ B . &nbsp2x C . &nbspx D . &nbsp$$\frac{1}{{2x}}$$

If $$sec\theta = x + \frac{1}{{4x}}$$ $$\left( {{0^ \circ } < \theta

Question

If $$sec\theta = x + \frac{1}{{4x}}$$ $$\left( {{0^ \circ } < \theta < {{90}^ \circ }} \right)$$ then $$sec\theta $$ + $${\text{tan}}\theta $$ is equal to?

Options:

A . $$\frac{x}{2}$$

B . 2x

C . x

D . $$\frac{1}{{2x}}$$

Answer: Option B

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