If r,s are the roots of the equation x^{2}-px+q=0, then what is the equation of the curve whose roots are ([1/r] + s) and ([1/s]+r)?

Options:

A . px2-q(1-p)x+(1+q2)=0

B . qx2+(p-q)x+(q2-1)=0

C . (p-q)x2+pqx-(p+1)(q+1)=0

D . qx2-p(q+1)x+(1+q)2=0

E . qx2-p(q+1)x+(1+q)=0

Answer: Option D : D option dput r=1 and s=1, then p=2 and q=1.Roots of the curve’s equation = 2,2Substitute values of p,q,r,s in options to check where 2,2 satisfy as roots. This happens only in option (d)

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