Question
If p = 99, then the value of p(p2 + 3p + 3) will be?
Answer: Option B
$$\eqalign{
& p\left( {{p^2} + 3p + 3} \right) \cr
& = {p^3} + 3{p^2} + 3p + 1 - 1 \cr} $$
(On adding and subtracting one both side)
$$\eqalign{
& = {\left( {p + 1} \right)^3} - 1 \cr
& = {\left( {99 + 1} \right)^3} - 1 \cr
& = {100^3} - 1 \cr
& = 1000000 - 1 \cr
& = 999999 \cr} $$
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$$\eqalign{
& p\left( {{p^2} + 3p + 3} \right) \cr
& = {p^3} + 3{p^2} + 3p + 1 - 1 \cr} $$
(On adding and subtracting one both side)
$$\eqalign{
& = {\left( {p + 1} \right)^3} - 1 \cr
& = {\left( {99 + 1} \right)^3} - 1 \cr
& = {100^3} - 1 \cr
& = 1000000 - 1 \cr
& = 999999 \cr} $$
Was this answer helpful ?
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