If NaCl is doped with 10 − 3 m o l % S r C l 2 , then the concentration of cation vacancies will be Options: A . &nbsp1×10−3mol% B . &nbsp2×10−3mol% C . &nbsp3×10−3mol% D . &nbsp4×10−3mol%

Answer: Option A : A Each S r 2 + ion introduces one cation vacancy ⇒ number of cation vacancies = % mole of S r 2 + = 10 − 3 m o l %

If NaCl is doped with 10−3mol% SrCl2, then the concentration of cati

Question

If NaCl is doped with

10^{- 3} m o l

S r C l_{2}

, then the concentration of cation vacancies will be

Options:

A . 1×10−3mol%

B . 2×10−3mol%

C . 3×10−3mol%

D . 4×10−3mol%

Answer: Option A
:
A
Each

S r^{2} +

ion introduces one cation vacancy

\Rightarrow

number of cation vacancies = % mole of

S r^{2 +} = 10^{- 3} m o l

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