Question
If log 2 = 0.3010 and log 3 = 0.4771, the value of log5 512 is:
Answer: Option C
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log5 512 = \(\frac{\log512}{\log5}\)
= \(\frac{\log2^{9}}{\log(\frac{10}{2})}\)
= \(\frac{9\log2}{\log10-\log2}\)
= \(\frac{(9\times0.3010)}{1-0.3010}\)
= \(\frac{2.709}{0.699}\)
= \(\frac{2709}{699}\)
=3.876
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